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Does .999 repeating equal 1?

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  • Does .999 repeating equal 1?

    So I'm currently relearning Calculus and ran across a proof of this statement. I know we've had at least two threads on this before, but I think it's time for a third one to see if Apolyton has gotten any smarter since the last one.
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  • #2
    Jon Miller: MikeH speaks the truth
    Jon Miller: MikeH is a shockingly revolting dolt and a masturbatory urine-reeking sideshow freak whose word is as valuable as an aging cow paddy.
    We've got both kinds

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    • #3
      (note: this post has been closed to comments; comments about it on other pages will be deleted!) UPDATE!!: The saga continues at this post. MORE UPDATES, WITH REFUTATIONS! THE FINAL UPDATE! Every year I get a few kids in my...


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      • #4
        No they're not equal, they look completely different
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        • #5
          Racist!
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          "We confess our little faults to persuade people that we have no large ones." - François de La Rochefoucauld

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          • #6
            Is this really something people argue about?

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            • #7
              The evidence leads to that conclusion.
              No, I did not steal that from somebody on Something Awful.

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              • #8
                Yes.
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                "We confess our little faults to persuade people that we have no large ones." - François de La Rochefoucauld

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                • #9
                  Originally posted by Solly
                  0.9 does not equal 1
                  0.99 does not equal 1
                  0.999 does not equal 1
                  0.9999 does not equal 1

                  etc.

                  At what number of 9s does this progression become equal to 1?
                  QED
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                  • #10
                    loinburger's gone over to the dark side.
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                    "We confess our little faults to persuade people that we have no large ones." - François de La Rochefoucauld

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                    • #11
                      Originally posted by KrazyHorse
                      Look, people, the concept is simple:

                      If a does not equal b then there exists a number c not equal to 0 such that a - b = c

                      Find me the number c such that 1 - 0.9999.... = c
                      Obviously, c = 1 preceded by an infinite number of 0's
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                      • #12
                        x = .999999...
                        10x = 9.99999999...
                        10x - x = 9x = 9.999999999... - .999999999... = 9
                        x = 1

                        what does this prove? Well, since .9999... obviously doesn't equal one it proves that algebra is invalid.

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                        • #13
                          Originally posted by gribbler View Post
                          x = .999999...
                          10x = 9.99999999...
                          10x - x = 9x = 9.999999999... - .999999999... = 9
                          x = 1

                          what does this prove? Well, since .9999... obviously doesn't equal one it proves that algebra is invalid.
                          Down with Muslim math!
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                          "We confess our little faults to persuade people that we have no large ones." - François de La Rochefoucauld

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                          • #14
                            Both numbers are rational. If two rational numbers a and b are different, then c=(a+b)/2 exists and is also a rational number. There's no such number for 1 and 0.(9), therefore they are the same.
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                            • #15
                              Originally posted by Lorizael View Post
                              Asher thought that .9 repeating isn't one?

                              Asher, are you sure you're a compsci major?
                              If there is no sound in space, how come you can hear the lasers?
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