So I'm currently relearning Calculus and ran across a proof of this statement. I know we've had at least two threads on this before, but I think it's time for a third one to see if Apolyton has gotten any smarter since the last one.
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Does .999 repeating equal 1?
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Does .999 repeating equal 1?
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"We confess our little faults to persuade people that we have no large ones." - François de La RochefoucauldTags: None
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Jon Miller: MikeH speaks the truth
Jon Miller: MikeH is a shockingly revolting dolt and a masturbatory urine-reeking sideshow freak whose word is as valuable as an aging cow paddy.
We've got both kinds
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He also hates Texans and Australians, he does diversify." ~ Braindead
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Racist!Click here if you're having trouble sleeping.
"We confess our little faults to persuade people that we have no large ones." - François de La Rochefoucauld
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loinburger's gone over to the dark side.Click here if you're having trouble sleeping.
"We confess our little faults to persuade people that we have no large ones." - François de La Rochefoucauld
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Originally posted by KrazyHorseLook, people, the concept is simple:
If a does not equal b then there exists a number c not equal to 0 such that a - b = c
Find me the number c such that 1 - 0.9999.... = c<p style="font-size:1024px">HTML is disabled in signatures </p>
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Originally posted by gribbler View Postx = .999999...
10x = 9.99999999...
10x - x = 9x = 9.999999999... - .999999999... = 9
x = 1
what does this prove? Well, since .9999... obviously doesn't equal one it proves that algebra is invalid.Click here if you're having trouble sleeping.
"We confess our little faults to persuade people that we have no large ones." - François de La Rochefoucauld
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Both numbers are rational. If two rational numbers a and b are different, then c=(a+b)/2 exists and is also a rational number. There's no such number for 1 and 0.(9), therefore they are the same.Graffiti in a public toilet
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