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A woman has two children, at least one of which is a boy...
There are 4 equally likely situations, given no info. These are
Bb, Bg, Gb, Gg - where the size of letter indicates oder of birth.
Gg is ruled out by the statement that she has at least one boy. In only 1 case of the 3 remaining does she have 2 boys, so the probability is 1/3
Note - this changes if you specify some defining feature about the stated boy that only one of a pair could possess - such as being the eldest. Then the probability, as expected, becomes 1/2
With two children there are four equally probable outcomes:
1. Both are boys;
2. First is a boy, second is a girl;
3. First is a girl, second is a boy;
4. Both are girls.
By definition, outcome #4 is excluded, so we have three left. Only one of these has a boy as the other child. Therefore the probability is indeed 1/3.
Edit: Chowlett said the same thing, but got his post in ahead of me.
"THE" plus "IRS" makes "THEIRS". Coincidence? I think not.
from what I understand, correct, but unfortunately I'm always told that my understanding of prob stat is off
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You provide no source. You PROVIDE NOTHING! And yet you want to destroy capitalism.. you criminal..." - Fez
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“I give you a new commandment, that you love one another. Just as I have loved you, you also should love one another. By this everyone will know that you are my disciples, if you have love for one another.”
- John 13:34-35 (NRSV)
If we postulate a species which has three sexes, evenly distributed, one of which is male, then the probability is 1/5. Proof is left as an exercise to the student. . .
"THE" plus "IRS" makes "THEIRS". Coincidence? I think not.
It's 1/2. The probability of either offspring being a boy is 1/2. If you know what one is, then the problem reduces to: a woman has one child of unknown gender: the probability it's a boy is: ___
The two births are independent events.
"The purpose of studying economics is not to acquire a set of ready-made answers to economic questions, but to learn how to avoid being deceived by economists."
-Joan Robinson
Originally posted by Chowlett
The argument holds assuming they have a 1:1 distribution of male and female births.
But assuming only makes an ass out of you and me .
“I give you a new commandment, that you love one another. Just as I have loved you, you also should love one another. By this everyone will know that you are my disciples, if you have love for one another.”
- John 13:34-35 (NRSV)
On the other hand if you are looking at the population of women with 2 children at least one of which is a male, then yes, the probability of the other being a male is 1/3... so it really depends on how the problem is worded and what it's asking for.
"The purpose of studying economics is not to acquire a set of ready-made answers to economic questions, but to learn how to avoid being deceived by economists."
-Joan Robinson
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