Math Game

[Chowlett]

Re: Case for the defence

Originally posted by Big Crunch

Edit. Damned idée fix.

I think that's idée fixe. Feminine.

Correct on the perfectness, and shade - correct on the Engilsh interpretation of Feigenbaum's number.

[shade]

Originally posted by Q Cubed
Prove that Sqrt(11) does not exist as a rational number using only axiomatic methods.

If sqrt(11) was a rational number it could be written as P/Q with P&Q integer values wich can't be simplified anymore(ie: 5 and 21 ok,but 15 and 21 not since both still can be devided by 3).

So we have
sqrt(11)=P/Q
<=>11=P²/Q²
this means that P² can be devided by Q² so P² can be devided by Q.What means that P and Q have a at least a common factor BUT we stated that this isn't so=> sqrt(11) is no rational number.


easy
(this thing drove the Pythagorean school almost mad)

Shade

[KrazyHorse]

You forgot to prove that Sqrt(11) is not an integer. Easy enough, but it's a necessary step (otherwise you've also proven that sqrt(n) is irrational for all n natural numbers)

[Caesar the Great]

this is for a comp algorithm i'm trying to write....

1) find the general term for the sum of the first n numbers of the series

2) find the sum n --> infinity

1 - 1/9 + 1/45 - 1/189 ... + [(-1)^(n-1)]/(3^n-1)(2n - 1)

[shade]

Originally posted by KrazyHorse
You forgot to prove that Sqrt(11) is not an integer. Easy enough, but it's a necessary step (otherwise you've also proven that sqrt(n) is irrational for all n natural numbers)

[edit: put something really stupid here,but problems solved now ]

Why sqrt(11) isn't an integer=> based on intuition

9<11<16
take sqrt
3 since we know there are no integers between 3 and 4 sqrt(11) isn't an integer ergo Q >1(had to put that too in the previous post)

(btw this one(sqrt(11) is rather ambigious to prove sqrt(2) is clearer)

[Dauphin]

dividors(or whatever it is called in English

Denominator

[shade]

strange...I'm glad I get my math in Dutch(although this sometimes gives problems for translations).

Still noone who found a way to create 24 by only using 1,3,4,6 and (,+,-,x,:,)



Shade

[Caesar the Great]

dammit i've gotten both 23 and 25 but not 24....

[shade]

It really isn't that hard.(just think what multiplication will give you 24 and think how you can write it)

this is for a comp algorithm i'm trying to write....

1) find the general term for the sum of the first n numbers of the series

2) find the sum n --> infinity

1 - 1/9 + 1/45 - 1/189 ... + [(-1)^(n-1)]/(3^n-1)(2n - 1)]

Since it's for a computer program just use the recursive one and for nr2 never mind infinity that's something a computer can't handle==> let the loop go until
[(-1)^(n-1)]/(3^n-1)(2n - 1)]<10^x (and choose your x according to the accuracy)
(or you could try something goniometric)

Shade

[Caesar the Great]

well the whole purpose is that i won't have to loop with a general formula....

the obvious answer is 4 x 6 x 1^3 but i don't think i can use exponents....

[shade]

the obvious answer is 4 x 6 x 1^3

Well it is 24

but i don't think i can use exponents....

And you are right here to so I'm sorry this isn't the right answer.
(but you are getting very close,think of other ways to write 4x6)

Shade

[KrazyHorse]

Give us the damn answer already.

I get a sneaking suspicion this is a trick question.

[KrazyHorse]

c) 0.00000007151=P of W the NL

0.00000007151=Probability of Winning the National(?) Lottery

It's the same odds as the 6/49 over here; 1/13900000 or so

[shade]

Originally posted by KrazyHorse
Give us the damn answer already.

I get a sneaking suspicion this is a trick question.

tsjtsjtsj

6/(1-3/4)=24


Don't say that it is so hard c'mon.(no need for differential equations,no need for transformation to Besselfunctions,just plain simple baby math.)

Shade

[KrazyHorse]

F#ck.