Okay....let us assume that A = B
Then, multiply by A: = B2 = AB
Subtract B square: A2 - B2 = AB - B2
Factor: (A+B)(A-B) = (A-B)B
Divide by (A-B): A+B = B
Now remember, A=B, so substitute "A" for "B"....
....A+A = A [that is 2A = A]
Divide by A: 2 = 1 or by the associate property of addition:
-------------> 1 = 2
Thus, 1+1 cannot equal 2, because 1 = 2.
QED.
[Unless, of course 1 = 0, in which case my whole proof falls to pieces.
]
Then, multiply by A: = B2 = AB
Subtract B square: A2 - B2 = AB - B2
Factor: (A+B)(A-B) = (A-B)B
Divide by (A-B): A+B = B
Now remember, A=B, so substitute "A" for "B"....
....A+A = A [that is 2A = A]
Divide by A: 2 = 1 or by the associate property of addition:
-------------> 1 = 2
Thus, 1+1 cannot equal 2, because 1 = 2.
QED.

[Unless, of course 1 = 0, in which case my whole proof falls to pieces.

Comment