What do you think of this?

[Stefan Härtel]

Here's the first couple of graphics from my coming scenario. No details are yet to be revealed, but guesses are premitted
What do you think of this?

[Case]

That math stuff makes my head hurt

The graphics look great though I'd guess that it's some kind of exploration scenario.

[POTUS]

I don't do math.

Nice graphic.

[Arthedain]

really nice waterfall!

[Stefan Härtel]

That's supposed to be [i]easy](i] stuff I've got to know for my final exams in May (Meaning: I won't ever make it).

I just noticed you can't properly see the unit in the lower left corner after I've cut off the shield from the screenshot graphic.

The waterfall, BTW, will be only a small one of many elements in this scenario.

[tanelorn]

Is he a stone-age hunter?
A Crusoe-type stranded on some island perhaps?

[curtsibling]

Looks a bit Aztec!

Maths?

That's all Von Braun talk to me!

[:) Smiley]

You forgot about the 3 * (-e^-x) terms in the binomial square

[Harry Tuttle]

(3-(e^-x))(3-(e^-x))=9-3(e^-x)-3(e^-x)e^x Owwwww, a blood vessel just burst....

[Stefan Härtel]

Well, the basic point is that the result must be:
f'(x)=(3-e^-x)² if f(x) is what would be F(x).
I personally think it must be F(x)=(x-e^-x)³; but I'd love to be proved otherwise (basically this is just a maths problem that's been keeping me occupied the other night, and I wanted to hear a second opinion).

Is he a stone-age hunter?
A Crusoe-type stranded on some island perhaps?

Nope. No island.

Looks a bit Aztec!

Closer, but still far away.

[Mercator]

The integral will be much more complicated than that... You also have the chain rule to worry about.

Try typing in the formula on this site:

http://integrals.wolfram.com/index.en.cgi

(Be sure to use uppercase E for e)

[Stefan Härtel]

The result doesn't show (it won't load the image)

If F(x) would be (x-e^-x)³, then f(x) would be, according to the chain rule: f(x)=(3-3^-x)²; or would it? According to
f'(x)=2*(3-e^-x)*e^-x if f(x)=(3-e-^x)²

In another calculation, however, f'(x) would be f'(x)=3*(x-e^-x)*(3-e^-x)

This is sick

[curtsibling]

OK, Stefan!

Spill the beans!

What is the scenario about?
Not mathematics surely?

[Mercator]

Originally posted by Stefan Härtel
The result doesn't show (it won't load the image)

I attached the image I got... It looks rather more complicated than the possible outcomes you gave. I'm not sure if that's because the program tries to write out everything in full... I.e. it would say x² - 2x + 1 rather than (x - 1)².

If F(x) would be (x-e^-x)³, then f(x) would be, according to the chain rule: f(x)=(3-3^-x)²; or would it?

No, it would be:

3 * (x - e^-x)² * (1 + e^-x)

So you made two mistakes:
- The multiplier of 3 is outside the square. I.e. the derivative of x³ is 3(x²), not (3x)².
- You have to take the derivative of the part in parentheses as well, and use the chain rule... that's the (1 + e^-x) at the end.

This is sick

I'll say... I'm glad I got that behind me. Not that the statistical maths I have to deal with is any easier, though.

EDIT: I forgot the minus in (1 + e^-x)

[Stefan Härtel]

I have much to learn (I've got one point out of 15 at best, that's a 5- mark, but it's enough since I'm good at English).

OK, Stefan!

Spill the beans!

What is the scenario about?
Not mathematics surely?

No, I just posted the poll because I went nuts about the problem

I can't tell you exactly what the scenario will be about because that'd be telling too much. But I can tell you that it's an adventure scenario set in pre-Colombian Ecuador. I've got some very cool ideas so far, but I don't want to tell because that'd spoil too many surprises.