Originally posted by sabrewolf
but anyway. time does "change" while going faster and faster. the nearer to the speed of light, the slower your time looks like from outside. (note: this has been experimentaly proven to be true!). Dt' = Dt * SQR(1-(v2)/c(v2))
but anyway. time does "change" while going faster and faster. the nearer to the speed of light, the slower your time looks like from outside. (note: this has been experimentaly proven to be true!). Dt' = Dt * SQR(1-(v2)/c(v2))
I think you have messed up your tags.
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