Brain teaser thread

[Az]

oh common , UR.

you take one of the sides of the square, and place perpendiculary 6 lines in equal distances from each other, and the other sides of the square.

I would draw it, but it's so plain that it sucks.

[Immortal Wombat]

*slaps self*

[Urban Ranger]

Originally posted by Azazel
oh common , UR.

you take one of the sides of the square, and place perpendiculary 6 lines in equal distances from each other, and the other sides of the square.

I would draw it, but it's so plain that it sucks.

Dang you

Your turn for a question.

[Az]

hmmmm.

I can't think of nothing out of the blue, so I'll skip this turn. actually, IW should ask the question, since he answered first.

[Az]

ok, I think I managed to scrape something up.

take 3 squares and place them together like this:

[][]
[]

divide them into 4 shapes, equal in size and form.

[Zero-Tau]

Like this:

[][]()()
[]{}{}()
/\{}
/\/\

[Zero-Tau]

Since Azazel seems to have left (and because I know that my answer is correct ), here's the next riddle.

One day Ming was careless enough to leave the forums unattended for a while. When he came back, he found that a lot of new people had arrived. Of these, 63 were simply screaming for a ban.
There were no DLs among the 63.
All 63 fell into at least one, possibly two or three, of these categories: Threadjacker, flamer, spammer.
There was a total of 42 spammers.
There was a total of 20 threadjackers.
There was a total of 30 flamers.
There was 5 people who were both spammers, flamers, and threadjackers.
All people who were flamers and threadjackers were also spammers.
There was twice as many people who were only spammers, as there was people who were only threadjackers.

How many people were only flamers?

[Lemmy]

i know it.
but i don't have a riddle, so i'll just shut up

[Zero-Tau]

Mmmkay...

Everyone, just go on without me. I'm going to bed. G'night.

[Japher]

18 flamers only
30 spammers
15 threadjackets

[Japher]

Is that correct?

[JohnM2433]

Exactly 12 people were only flamers.

[Japher]

12 can't be right.

That would leave 51 others, from which you would end up with 34 only spammers and 17 only threadjackers. If 5 are threadjackers, spammers, and flammers tha would yeild 22 threadjackers (5+17) total, not 20.

[JohnM2433]

Japher, I'm almost certain my answer is correct. I checked my math very thoroughly. I that found a nice Venn diagram helps to solve this problem. Just so that you can confirm it, though, I got:

18 people are only spammers
9 people are only threadjackers
12 people are only flamers
6 people are both spammers and threadjackers, but not flamers.
13 people are both smammers and flamers, but not threadjackers.
No one is both a threadjacker and a flamer, but not a spammer.
The remaining 5 people are threadjackers, spammers, and flamers.

I suppose that if you interpretted "There was 5 people who were both spammers, flamers, and threadjackers" to mean at least 5 people, rather than exactly 5, more than one correct answer might be possible.

So...

There are two words in the English language that both begin and end with "he". What are they?

If you only get one, feel free to post it by itself and let someone else get the other one.

[JohnM2433]

Originally posted by Japher
12 can't be right.

That would leave 51 others, from which you would end up with 34 only spammers and 17 only threadjackers. If 5 are threadjackers, spammers, and flammers tha would yeild 22 threadjackers (5+17) total, not 20.

The non-flamers are not all only spammers or only threadjackers. Indeed, if they were, then the flamers would have to be only flamers as well, since no threadjacker or spammer would be a flamer. That would contradict the given statement that "There was 5 people who were both spammers, flamers, and threadjackers". And it would make no sense to add that figure to the number of people who are only threadjackers, since all 63 have already been accounted for.