Java Help

[devilmunchkin]

Help!
My boyfriend has been trying to figure out this program for his java class for over a week..to no avail. The teacher won't help him and he's at his wits end. I think it's supposed to be a calculator program. He says he's having trouble getting the operator character to read into the program. Can any of you figure this out? Here's what he has for his program so far:

import java.util.StringTokenizer;

import java.text.DecimalFormat;

import javax.swing.JOptionPane;

import java.io.*;


public class Calculator

{

public static void main(String [] arg) throws IOException


{

BufferedReader keyboard = new
BufferedReader(new InputStreamReader(System.in));


StringTokenizer tokenizer;

int results, results2, results3, results4, num1, num2/*, operator*/, test;

String operator;//, num1, num2;

String pane1, pane2;


pane1 = JOptionPane.showInputDialog("The purpose of this program is to mimic a calculator."
+ "\n\n\nPlease enter the data in this format | 1 + 2 | .");



tokenizer = new StringTokenizer (pane1);

num1 = Integer.parseInt(tokenizer.nextToken());

operator = tokenizer.nextToken();

num2 = Integer.parseInt(tokenizer.nextToken());

test = (char) '+';

results = (num1 + num2);

results2 = (num1 - num2);

results3 = (num1 * num2);

results4 = (num1 / num2);



if (operator = test )
JOptionPane.showMessageDialog(null, "Your results are " + results + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);
/*
else if (test == '-')
JOptionPane.showMessageDialog(null, "Your results are " + results2 + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);

else if (test == '*')
JOptionPane.showMessageDialog(null, "Your results are " + results3 + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);

else if (test == '/')
JOptionPane.showMessageDialog(null, "Your results are " + results4 + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);



switch (operator)
{
case '+' : JOptionPane.showMessageDialog(null, "Your results are " + results + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);

}

*/






System.exit(0);

}





}

[Asher]

Try this

import java.util.StringTokenizer;

import java.text.DecimalFormat;

import javax.swing.JOptionPane;

import java.io.*;


public class Calculator

{

public static void main(String [] arg) throws IOException


{

BufferedReader keyboard = new
BufferedReader(new InputStreamReader(System.in));


StringTokenizer tokenizer;

int results, results2, results3, results4, num1, num2/*, operator*/, test;

String operator;//, num1, num2;

String pane1, pane2;


pane1 = JOptionPane.showInputDialog("The purpose of this program is to mimic a calculator."
+ "\n\n\nPlease enter the data in this format | 1 + 2 | .");



tokenizer = new StringTokenizer (pane1);

num1 = Integer.parseInt(tokenizer.nextToken());

operator = tokenizer.nextToken();

num2 = Integer.parseInt(tokenizer.nextToken());

//test = (char) '+';

results = (num1 + num2);

results2 = (num1 - num2);

results3 = (num1 * num2);

results4 = (num1 / num2);



if (operator.equals("+") )
JOptionPane.showMessageDialog(null, "Your results are " + results + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);
/*
else if (operator.equals("-"))
JOptionPane.showMessageDialog(null, "Your results are " + results2 + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);

else if (operator.equals("*"))
JOptionPane.showMessageDialog(null, "Your results are " + results3 + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);

else if (operator.equals("/"))
JOptionPane.showMessageDialog(null, "Your results are " + results4 + ".", "Your results are...", JOptionPane.INFORMATION_MESSAGE);


*/






System.exit(0);

}





}

[Jack_www]

Was he suppost to write a program that acts like a caculator. I had to do the same thing in my java intro class. Asher program is a better way going about it.

[devilmunchkin]

asher: thank you thank you thank you!

[SlowwHand]

And they said Asher wasn't a gawd. HA!

[Ted Striker]

See Asher knows all that open source crap too

[Asher]

The guy who made Java is an alumnus of my uni, we were forced at gunpoint to use Java in our first year due to an abundance of Sun equipment and software.

dm: no problem.

Tell him he should catch that IOException he throws if he wants full marks.

[Asher]

I'm also confused why he needs a BufferedReader and stuff, too.

[Asher]

Because I'm anal and bored at work: a clean version of that program.

import java.util.StringTokenizer;
import javax.swing.JOptionPane;

public class Calculator 
{
	public static void main(String[] arg)
	{
		StringTokenizer tokenizer;
		int num1, num2, result;
		String operator, pane1, pane2;

		pane1 = JOptionPane.showInputDialog("The purpose of this program is to mimic a calculator."
				+ "\n\n\nPlease enter the data in this format | 1 + 2 | .");
		tokenizer = new StringTokenizer(pane1);

		num1 = Integer.parseInt(tokenizer.nextToken());
		operator = tokenizer.nextToken();
		num2 = Integer.parseInt(tokenizer.nextToken());

		if (operator.equals("+"))
			result = num1 + num2;
		else if (operator.equals("-"))
			result = num1 - num2;	
		else if (operator.equals("*"))
			result = num1 * num2;
		else
			result = num1 / num2;	
		JOptionPane.showMessageDialog(null,
			"Your results are " + result + ".",
			"Your results are...",
			JOptionPane.INFORMATION_MESSAGE);
		
		System.exit(0);
	}
}

[Kuciwalker]

Originally posted by Asher
I'm also confused why he needs a BufferedReader and stuff, too.

Because using the stupid popup windows as input boxes is gay?

[Asher]

But popup windows and input boxes don't need a buffered reader, nor do they throw IOExceptions.

[Kuciwalker]

So?

It looks a lot prettier if you do input from the console.

Plus, the chances of it throwing an IOException is nil, unless you've got something seriously wrong anyways.

[Asher]

The point was he didn't need a buffered reader or an IOException since he wasn't using console input.

[Kuciwalker]

Yes he was. Wasn't he?

EDIT: n/m, you're right.