Originally posted by jones
principle of choice (combinations)
Pr(
(2/3)^3 - base chance of a winning 3
(
3c1 (3)- to go 4 rounds, d must win 1
4c2 (6)- " 5 " 2
)
(1/3)^n++ - pr d will win 1 more round each time
Bleh..i'm terrible at explaining math. However,
principle of choice (combinations)
Pr(
(2/3)^3 - base chance of a winning 3
(
3c1 (3)- to go 4 rounds, d must win 1
4c2 (6)- " 5 " 2
)
(1/3)^n++ - pr d will win 1 more round each time
Bleh..i'm terrible at explaining math. However,
monte carlo
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