a compact set on the reals will always have finite measure

[Kuciwalker]

right?

[bumfister]

What does this have to do with fisting or dickgirls?

[Kuciwalker]

More importantly, if E is a compact set [on whatever] then exists delta forall x,y in E d(x,y) < delta, right?

[bumfister]

d(x,y) << dickgirls

[EPW]

I thiought you could divide the reals foorever and eveer

[Kuciwalker]

nvm, I didn't realize I could use without proof the fact that continuous functions on a compact set are uniformly continuous

[KrazyHorse]

a compact set on the reals will always have finite measure

Bolzano Weierstrass?

[ShaneWalter]

What are you even talking about.

[Kuciwalker]

My math homework.

[RGBVideo]

What does this have to do with fisting or dickgirls?

**** off

[KrazyHorse]

nvm, I didn't realize I could use without proof the fact that continuous functions on a compact set are uniformly continuous

That follows straight from the definition of compactness.

[Asher]

I'm starting to worry about your compsci education. You really should not be taking any pure math-heavy courses by your senior year unless you are going into theoretical computer science.

[Kuciwalker]

I'm a math major. This is a required class.

Also, I pretty much ran out of classes in the theory department on the CS side.

[Asher]

Math major? Not CS?

[loinburger]

Invalid major