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  • Need some basic mathematics help, yo

    So I'm sure the equation we've been given to work with in this assignment is wrong. Basically we're to divide a cross section of a wall at home into its' basic elements (ie gypsum, fibreglass, cedar panelling, etc.)

    Each element has its own R value, and per each elements' thickness it arrives at a level of insulation that's proportional to the whole.

    Element 1 of my wall is about 4.7% of the entire insulation value

    Element 2 - 3.9%

    Element 3 - 45.5%

    Element 4 - 36.4%

    Element 5 - 5.3%

    Element 6 - 4.3%

    Which, (obviously enough) adds up to ~100%

    From there, we're to find out what amount of temperature is lost in each element from inside temperature to outside temp. Inside temp is 22c, outside -30c. Simple enough, right?

    Though the formula we're being given to do just that is as follows:

    ChangeTemp = [To + Ti] x [element R value divided by total R value, ie.) 5% would be equal to 5/100]

    Plugging in the numbers that way doesn't work. This hand out is likely a bad photocopy, or somethingI know there's some sort of square or inverse action I have to be applying here, but am not mathematically inclined enough to know! Anyone?

  • #2
    Therefore for the temp decrease in the %4.7 value element:

    ChangeTemp = [52c] x [.047] = 2.44degree loss

    while temp decrease in the (better) %5.3 value element

    =[52c] x [.053] = 2.756degree loss

    Doesn't make sense. As the proportional insulative value goes up so does the heat loss? There's some little square or something missing in that formula and it seems like it should be so easily noted. AHHHHHHH!

    Comment


    • #3
      Should be Ti - To
      12-17-10 Mohamed Bouazizi NEVER FORGET
      Stadtluft Macht Frei
      Killing it is the new killing it
      Ultima Ratio Regum

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      • #4
        Other than that, the formula is correct. Your second post applies the formula properly.
        12-17-10 Mohamed Bouazizi NEVER FORGET
        Stadtluft Macht Frei
        Killing it is the new killing it
        Ultima Ratio Regum

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        • #5
          Well in the initial formula it's To + Ti with a little arrow over the plus sign pointing towards Ti. I assume that just means to find the real difference in temperature between the two.

          Now changing it to Ti - To does nothing, doesn't it?

          Comment


          • #6
            Reasoning is as follows: say you have a pane of glass 10 cm thick. Inside T = 30C outside T = 0C

            T(x) = (30 - 3x)C where x is the distance from the inner wall measured in cm. IOW the temperature goes linearly from Ti to To

            Now imagine that instead of 10 cm glass you have 9cm glass then 1 cm glass. T at interface is 3C, so delta T through thick piece is 27C and delta T through thin piece is 3C. If total R value is Rt then R of 9 cm piece is 0.9Rt and R of 1 cm piece is 0.1Rt. Formula thus works.
            12-17-10 Mohamed Bouazizi NEVER FORGET
            Stadtluft Macht Frei
            Killing it is the new killing it
            Ultima Ratio Regum

            Comment


            • #7
              Originally posted by Zylka
              Now changing it to Ti - To does nothing, doesn't it?
              When you subtract a negative number it becomes adding a positive number.
              (\__/) 07/07/1937 - Never forget
              (='.'=) "Claims demand evidence; extraordinary claims demand extraordinary evidence." -- Carl Sagan
              (")_(") "Starting the fire from within."

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              • #8
                Originally posted by KrazyHorse
                Other than that, the formula is correct. Your second post applies the formula properly.
                but it isn't correct. By my second post, one layer with a 4.7% proportion of insulative value loses only 2.9 degrees in temperature - when the layer with 45.5% proportion of insulative value loses 23.7 degrees.

                You understand how that can't make sense, right?

                There are all sorts of little indistinct scribbles in/around the formula.. is there an inverse or something like that that I'm missing?

                Comment


                • #9
                  Originally posted by Urban Ranger

                  When you subtract a negative number it becomes adding a positive number.
                  Uh, yeah. Which comes up with the exact same value as if I had added the two temps by real scale. 52 degrees, either way you cut it

                  Comment


                  • #10
                    Basically, delta T does not represent a heat loss. In actuality the heat flow through each of the segments is exactly equal. This is a conservation principle. If more heat flowed through layer one than through layer two then there would be a buildup of heat somewhere. Now, since heat flow through each segment is equal:

                    H1 = deltaT1/R1
                    H2 = deltaT2/R2
                    ...
                    Hn = deltaTn/Rn
                    Htotal = deltaTtotal/Rtotal

                    H1 = H2 =...= Hn = Htotal = deltaTtotal/Rtotal
                    deltaTi/Ri = deltaTtotal/Rtotal
                    deltaTi = deltaTtotal * (Ri/Rtotal)

                    which is your formula
                    12-17-10 Mohamed Bouazizi NEVER FORGET
                    Stadtluft Macht Frei
                    Killing it is the new killing it
                    Ultima Ratio Regum

                    Comment


                    • #11
                      Originally posted by Zylka


                      but it isn't correct. By my second post, one layer with a 4.7% proportion of insulative value loses only 2.9 degrees in temperature - when the layer with 45.5% proportion of insulative value loses 23.7 degrees.

                      You understand how that can't make sense, right?

                      There are all sorts of little indistinct scribbles in/around the formula.. is there an inverse or something like that that I'm missing?
                      NO. THE FORMULA IS CORRECT. THICKER LAYERS OF INSULATION HAVE A GREATER CHANGE IN TEMPERATURE ACROSS THEM.
                      12-17-10 Mohamed Bouazizi NEVER FORGET
                      Stadtluft Macht Frei
                      Killing it is the new killing it
                      Ultima Ratio Regum

                      Comment


                      • #12
                        LOUD NOISES
                        "The issue is there are still many people out there that use religion as a crutch for bigotry and hate. Like Ben."
                        Ben Kenobi: "That means I'm doing something right. "

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                        • #13
                          Originally posted by KrazyHorse
                          Reasoning is as follows: say you have a pane of glass 10 cm thick. Inside T = 30C outside T = 0C

                          T(x) = (30 - 3x)C where x is the distance from the inner wall measured in cm. IOW the temperature goes linearly from Ti to To

                          Now imagine that instead of 10 cm glass you have 9cm glass then 1 cm glass. T at interface is 3C, so delta T through thick piece is 27C and delta T through thin piece is 3C. If total R value is Rt then R of 9 cm piece is 0.9Rt and R of 1 cm piece is 0.1Rt. Formula thus works.
                          I've already accounted for thicknesses in arriving at each elements' R.

                          As they have been arrived - element 1 has a 4.7% worth of the entire walls' insulative valie. Element 2 has a 3.9% worth of the entire walls' insulative value.

                          Using the forumla you find correct - the first element (thickness and Btu already accounted for), with a HIGHER proportion of the walls' overall insulation - LOSES more temperature than the lesser element of 3.9%. That does not make sense.

                          Comment


                          • #14
                            Originally posted by Zylka
                            but it isn't correct. By my second post, one layer with a 4.7% proportion of insulative value loses only 2.9 degrees in temperature - when the layer with 45.5% proportion of insulative value loses 23.7 degrees.

                            You understand how that can't make sense, right?
                            You mean because 52*.047 != 2.9?

                            Other than that...
                            "In the beginning was the Word. Then came the ******* word processor." -Dan Simmons, Hyperion

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                            • #15
                              An analogy:

                              I have a garden hose which is comprised of two segments: segment one has radius 2 cm and segment two has radius 1 cm. I turn on the hose and measure the velocity of the water flowing through each segment. To my great surprise, the water flows faster through segment 2 than through segment 1.

                              The total volume flow through each segment is the same (since otherwise the water would build up somewhere), but to maintain that flow through a tight section of hose (i.e. to maintain equivalent heat flow across a good insulator) the water needs to flow faster, velocitywise (i.e. the temperature difference needs to be greater).
                              12-17-10 Mohamed Bouazizi NEVER FORGET
                              Stadtluft Macht Frei
                              Killing it is the new killing it
                              Ultima Ratio Regum

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