How are the stats calculated.

[J Bytheway]

Profile! Please read at least the last few posts and all will be made clear. Preferably read all posts by MarkG in the thread.

[Apocalypse]

See? People don't even both to read threads already on the subject, much less the FAQ.

[J Bytheway]

I'd think people would be much more likely to read the FAQ than this bloated and somewhat confusing thread.

[Lemmy]

can you blame 'm for not reading this thread, its more than 340 posts, even i who has been following this haven't read everything...

[Apocalypse]

They could have skimmed through the last couple pages already.

[jdd2007]

i didnt feel like reading 13 pages. anyway, i didnt see any stats when they were under the avatar

[jdd2007]

make that 14 pages

[Apocalypse]

If you do 30 posts/page it is only 12

[FlameFlash]

Originally posted by Apocalypse
They could have skimmed through the last couple pages already.

You have a really high opinion of our fellow poster's habits don't you?

Finally looked at the FAQ. If I had any questions, they'd be solved now (especially the opst count thing). If this stuff was in the FAQ as well we'd see just us posting here.

Lemmy is right, (and although I've read all the posts) I'm still not sure as to what is going on... hence why the standing request for some of the math.

[FlameFlash]

posts per page? On my screen they're showing up 15 pages now...

[Dauphin]

You can set it in your options. The default is 20 posts per page. MarkG will no doubt be able to tell you what the preferred rate is.

[J Bytheway]

Originally posted by FlameFlash
hence why the standing request for some of the math.

Since it appears Mark is unwilling to tell us I tried to figure out the formula myself. It's not nearly so simple as I thought. I expected from the comment "A is logarithmically related to post count" that it would be of the form A = k * ln(PC) for some k - so I plotted A against ln(PC) to determine the value of k, but found that the relation is far from linear. The best relatively simple approximation I've found so far is A = FLOOR(1+0.074*ln(PC)^3.06) (pink line below). But as you can see it doesn't fit very well, especially for high post counts.

[Dauphin]

A = Floor((log PC)³,1) + 1

[J Bytheway]

What's a floor with two arguments?

[Apocalypse]

Originally posted by FlameFlash
You have a really high opinion of our fellow poster's habits don't you?

I'm just making a helpful suggestion. At many other forums, there'd be flaming.