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Q about interceptoin chance...

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  • Q about interceptoin chance...

    Since i'm not the best at math, i figured i'd ask the genius' in here for some help.



    Say i have 5 fighters in a town on intercept duty. Enemy sends in 1 bomber.

    The chance of a succesful bombing run would be (assuming a 50% intercept chance):

    .5 x .5 x .5 x .5 x .5 = .03125 or roughly 3%

    Assuming the first bomber is shot down via one of the 5 intercepters, then that next bombers chance for a succesful bombing run is =

    .5 ^ 4 = .0625 or roughly 6%

    And so on....... right?


    Now lets say i have 5 SAM infantry and 2 Mech infantry with a 30% and 20% intercept chance.

    The chance of a succesful bombing run, regardless of how many bombers are being sent, will always be:

    .7 ^ 5 x .8 ^ 2 = .1075 or roughly 10%

    Is that right, or do i have my math wrong? Do i also understand the gameconcept correctly that when a fighter intercepts a bomber it is taken out of consideration, but ground units with intercept ability remain active regardless of how many shoot downs?
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